Question

{4х-7у=-12{6х+3у=-18методом алгебраического сложения​ Смотреть ответ natali198112306 natali198112306 Ответ:4х-7у=-12        /×36х+3у=-18       /×712х-21у=-3642х+21у=-12654х=-162х=-162÷54х=-34×(-3)-7у=-12-12-7у=-12-7у=-12+12-7у=0у=0Объяснение:

Answer 1

To solve the system of equations using the method of algebraic addition, we need to eliminate one variable by adding the two equations together. Let's solve the given system of equations step by step:

Equation 1: 4x - 7y = -12 Equation 2: 6x + 3y = -18

To eliminate the variable "y," we can multiply Equation 1 by 3 and Equation 2 by 7:

3 * (4x - 7y) = 3 * (-12) 7 * (6x + 3y) = 7 * (-18)

Simplifying these equations, we get:

12x - 21y = -36 42x + 21y = -126

Now, we can add these two equations together:

(12x - 21y) + (42x + 21y) = -36 + (-126)

Simplifying further, we have:

54x = -162

Dividing both sides of the equation by 54, we find:

x = -162 / 54 x = -3

Now that we have the value of x, we can substitute it back into one of the original equations to find the value of y. Let's use Equation 1:

4x - 7y = -12

Substituting x = -3, we get:

4(-3) - 7y = -12 -12 - 7y = -12

Simplifying, we have:

-7y = 0

Dividing both sides of the equation by -7, we find:

y = 0

Therefore, the solution to the given system of equations is x = -3 and y = 0.

Please let me know if you have any further questions!