Question

Розв'яжіть рівняння: 1)(x+8)= 0; 2)(x+2)²-16-0

Answer 1

1) (x+8)= 0;
x = 0 - 8;

x = - 8

2) (x+2)²-16-0;
(x+2)² = 16;

1. x + 2 = - 4;

x = -6

2. x + 2 = 4;
x = 2
Відповідь: - 6, 2

Answer 2

1) (x+8) = 0

To solve this equation, we need to isolate the variable x.

First, let's subtract 8 from both sides of the equation to get rid of the constant term:

x + 8 - 8 = 0 - 8

This simplifies to:

x = -8

Therefore, the solution to the equation (x+8) = 0 is x = -8.

2) (x+2)² - 16 = 0

To solve this equation, we need to isolate the variable x.

First, let's simplify the equation by expanding the square:

(x+2)(x+2) - 16 = 0

This simplifies to:

(x² + 4x + 4) - 16 = 0

Next, combine like terms:

x² + 4x + 4 - 16 = 0

x² + 4x - 12 = 0

Now, let's factor the quadratic equation:

(x - 2)(x + 6) = 0

To find the values of x, we can set each factor equal to zero:

x - 2 = 0 or x + 6 = 0

Solving the first equation, we get:

x = 2

Solving the second equation, we get:

x = -6

Therefore, the solutions to the equation (x+2)² - 16 = 0 are x = 2 and x = -6.