Question

1.(y-1)(y^2+2y-4)= 2.(2a+3)^2= 3.a^2-(a-b)^2= Помогитееееее пжпжпжпжпж​

Answer 1

Ответ:

1.(y-1)(y^2+2y-4)=у³+2у²-4у-у²-2у+4=у³+у²-6у+4

2.(2a+3)^2=4а²+12а+9

3.a^2-(a-b)^2=а²-(а²-2аb+b²)=а²-а²+2аb-b²=2аb-b²=b(2а-b)

Объяснение:

Answer 2

1. (y-1)(y^2+2y-4) = Expanding the equation, we get: y(y^2+2y-4) - 1(y^2+2y-4) = y^3 + 2y^2 - 4y - y^2 -2y + 4 = y^3 + y^2 - 6y + 4

2. (2a+3)^2 = Expanding the square, we get: (2a+3)(2a+3) = 4a^2 + 6a + 6a + 9 = 4a^2 + 12a + 9

3. a^2 - (a-b)^2 = Expanding the square, we get: a^2 - (a^2 - 2ab + b^2) = a^2 - a^2 + 2ab - b^2 = 2ab - b^2

I hope this helps! If you have any further questions, please let me know.