Question

На 1м участке было в 5 раз больше кустов смородины,чем во 2м.После этого,как на 2й участок пересадили с первого участка 50 кустов и еще посадили на 2ом участке 60 кустов,то на участказ кустов стало поровну. Сколько кустов смородины было на каждом участке первоначально?

Answer 1

Пусть на втором участке было Х кустов.

Т.к. на первом участке в пять раз больше, значит на первом участке -  5Х кустов.

После того как на второй участок пересадили 50 кустов с первого участка и еще 60 кустов то получается, что на первом участке 5Х-50 кустов, а на втором Х+50+60=Х+110

Можно их приравнивать, т.к. они равны

и получается уравнение 5Х-50=Х+50+60

Отсюда находим Х

Х=40

Значит на втором участке было 40 кустов

Следовательно на первом 5х=5•40=200

Answer 2

#### Problem Analysis We are given two plots of land, and initially, the first plot has five times more currant bushes than the second plot. After transferring 50 bushes from the first plot to the second plot and planting an additional 60 bushes on the second plot, the number of bushes on both plots becomes equal. We need to determine the initial number of bushes on each plot. #### Solution Let's assume that the initial number of bushes on the second plot is x. According to the problem, the first plot has five times more bushes than the second plot, so the initial number of bushes on the first plot is 5x. After transferring 50 bushes from the first plot to the second plot, the number of bushes on the first plot becomes 5x - 50, and the number of bushes on the second plot becomes x + 50. After planting an additional 60 bushes on the second plot, the number of bushes on the second plot becomes x + 50 + 60 = x + 110. According to the problem, the number of bushes on both plots becomes equal, so we can set up the following equation: 5x - 50 = x + 110 Now, let's solve this equation to find the value of x. #### Calculation 5x - 50 = x + 110 Subtract x from both sides: 4x - 50 = 110 Add 50 to both sides: 4x = 160 Divide both sides by 4: x = 40 #### Answer The initial number of currant bushes on the first plot was 5x, which is 5 * 40 = 200 bushes. The initial number of currant bushes on the second plot was x, which is 40 bushes. Therefore, there were initially 200 currant bushes on the first plot and 40 currant bushes on the second plot.