Question

2а(2+b-c)-2b(a-b-c)+2c(a-b+c)​

Answer 1

Ответ:

Объяснение:

2а(2+b-c)-2b(a-b-c)+2c(a-b+c)​ = 4a+2ab-2ac-2ba+2b²+2bc+2ca-2bc+2c² = 2ab-2ba-2ac+2ca+2bc-2cb+4a+2b²+2c² = 4a+2b²+2c²

Answer 2

To simplify the expression 2a(2+b-c)-2b(a-b-c)+2c(a-b+c), you can use the distributive property and then combine like terms:

1. Distribute the constants and variables: = 2a2 + 2ab - 2ac - 2ba + 2b^2 + 2bc + 2ca - 2c*b + 2c^2

2. Combine like terms by grouping them: = (2a2 - 2ba + 2ca) + (2ab - 2bb) + (-2ac + 2b*c + 2c^2)

3. Simplify each group: = 4a - 2ab + 2ac + 2ab - 2b^2 - 2ac + 2b*c + 2c^2

4. Combine like terms again: = 4a - 2b^2 + 2c^2

So, the simplified expression is 4a - 2b^2 + 2c^2.