Question

при ходьбе в гору Турист идет на 2 км ч медленнее а с горы на 2 км ч быстрее чем при ходьбе по ровной местности восхождение на гору у туриста занимает 10 часов а спуск с горы 6 часов Какова скорость туриста по ровной местности

Answer 1

х - скорость на ровной поверхности

х-2 - в гору

х+2 - с горы

10(х-2)=6(х+2)

10х-20=6х+12

10х-6х=12+20

4х=32  

х=8

Ответ: 8 км/ч скорость на ровной поверхности.

Answer 2

Calculation of the Tourist's Speed on Flat Ground

To determine the tourist's speed on flat ground, we can use the information provided about their speed during uphill and downhill walks.

Let's denote the speed on flat ground as x km/h. According to the given information, the tourist walks 2 km/h slower uphill and 2 km/h faster downhill compared to walking on flat ground.

Given that the uphill climb takes 10 hours and the downhill descent takes 6 hours, we can set up the following equations:

Uphill Climb: Distance = Speed × Time 2 km/h slower than on flat ground = (x - 2) km/h Distance = (x - 2) km/h × 10 hours

Downhill Descent: Distance = Speed × Time 2 km/h faster than on flat ground = (x + 2) km/h Distance = (x + 2) km/h × 6 hours

Since the distances for both uphill and downhill are the same, we can equate the two equations:

(x - 2) km/h × 10 hours = (x + 2) km/h × 6 hours

Simplifying the equation:

10x - 20 = 6x + 12

Rearranging the equation:

10x - 6x = 12 + 20

4x = 32

Dividing both sides by 4:

x = 8

Therefore, the tourist's speed on flat ground is 8 km/h.