Question

4(3X + 1\2)+(3X + 1)-3 = 0

Answer 1

$\displaystyle 4\Bigg(3x + \frac{1}{2}\Bigg) + \Bigg(3x + 1\Bigg) - 1 = 0 \\\\\\\displaystyle 4\Bigg(3x + \frac{1}{2}\Bigg) + 3x+1-1 = 0 \\\\\\\displaystyle 12x+2+3x=0 \\\\\\\\displaystyle 15x+2=0 \\\\\\\displaystyle 15x = -2 \\\\\\\displaystylex \boxed{x=-\frac{2}{15}}$

Answer 2

To solve the equation 4(3x + 1/2) + (3x + 1) - 3 = 0, you'll need to follow these steps:

1. Distribute the 4 on the left side of the equation: 4(3x) + 4(1/2) + (3x + 1) - 3 = 0

2. Simplify the terms within parentheses: 12x + 2 + 3x + 1 - 3 = 0

3. Combine like terms: (12x + 3x) + (2 + 1 - 3) = 0 15x + 0 = 0

4. Simplify further: 15x = 0

5. Divide both sides by 15 to isolate x: 15x/15 = 0/15 x = 0

So, the solution to the equation is x = 0.