Question

2) 3/4 x=273) (2+3x)-(4x-7)=104) 2(x-1,5)+x=65) 0,4x-6= -12​

Answer 1

Объяснение:

2)3/4х=27 х=36

3)(2+3х)-(4х-7)=10 х=-1

4)2(х-1,5)+х=6 х=7

6)0,4х-6=-12 х=-15

Answer 2

Let's solve each of these equations step by step:

1. $\frac{3}{4}x = 27$

To solve for $x$, you can multiply both sides of the equation by $\frac{4}{3}$ to isolate $x$:

$x = 27 \times \frac{4}{3}$ $x = 36$

So, the solution to the first equation is $x = 36$.

2. $(2+3x)-(4x-7) = 10$

First, let's simplify the equation by removing the parentheses:

$2 + 3x - 4x + 7 = 10$

Combine like terms:

$-x + 9 = 10$

Now, subtract 9 from both sides of the equation to isolate $x$:

$-x = 10 - 9$ $-x = 1$

To solve for $x$, multiply both sides by -1:

$x = -1$

So, the solution to the second equation is $x = -1$.

3. $2(x-1.5) + x = 6$

First, distribute the 2 on the left side of the equation:

$2x - 3 + x = 6$

Combine like terms:

$3x - 3 = 6$

Now, add 3 to both sides of the equation to isolate $3x$:

$3x = 6 + 3$ $3x = 9$

Finally, divide both sides by 3 to solve for $x$:

$x = \frac{9}{3}$ $x = 3$

So, the solution to the third equation is $x = 3$.

4. $0.4x - 6 = -12$

Add 6 to both sides of the equation to isolate $0.4x$:

$0.4x = -12 + 6$ $0.4x = -6$

Now, divide both sides by 0.4 to solve for $x$:

$x = \frac{-6}{0.4}$ $x = -15$

So, the solution to the fourth equation is $x = -15$.