Question

Y=корень x+1 x=0 x=1 y=0

Answer 1

Ответ:

x+1=0+1=1

√y=√0=y ничему не принадлежит

Или корень уравнения с y, то там уже он написан(y=0)

Объяснение:

Ты непонятное объяснение дал(а), я как понял так и сделал.

Answer 2

It looks like you're providing some values for the variables in an equation, but it's not entirely clear what you're asking. If I understand correctly, you're giving the equation:

$y = \sqrt{x + 1}$

And you've provided some specific values for $x$ and $y$:

1. When $x = 0$, (y = 0.
2. When $x = 1$, (y = 0.

It seems like you want to verify these values for $y$ when $x$ is 0 and 1.

Let's check:

1. When $x = 0$: $y = \sqrt{0 + 1} = \sqrt{1} = 1$

So, when $x = 0$, $y = 1$, not 0.

2. When $x = 1$: $y = \sqrt{1 + 1} = \sqrt{2}$

So, when $x = 1$, $y = \sqrt{2}$, not 0.

It appears there is an error in the values you provided. If you have more information or a specific question, please let me know, and I'll be happy to assist further.