Question

5(x-2)=(3x+2)(x-2) chjxyj g;

Answer 1

Объяснение:

5x-10=3x-4

5x-3x=10-4

2x=6

x=6:2

x=3

Answer 2

$5(x-2)=(3x+2)(x-2)\\\\5x-10=3x^{2}-4x-4\\\\3x^{2}-4x-4-5x+10\\\\3x^{2}-9x+6=0\\\\D=81-72=9\\\\x_{1}=\frac{9+3}{6} =2\\\\x_{2}=\frac{9-3}{6} =1$

Answer 3

It appears that you've provided an equation: 5(x-2) = (3x+2)(x-2). To solve for x, you can follow these steps:

1. Distribute the terms on the right side of the equation: 5(x-2) = 3x(x-2) + 2(x-2)

2. Simplify further: 5x - 10 = 3x^2 - 6x + 2x - 4

3. Combine like terms: 5x - 10 = 3x^2 - 4x - 4

4. Move all terms to one side of the equation to set it equal to zero: 3x^2 - 4x - 4 - 5x + 10 = 0

5. Combine like terms again: 3x^2 - 9x + 6 = 0

6. Divide the entire equation by the greatest common divisor, which is 3 in this case: x^2 - 3x + 2 = 0

7. Factor the quadratic equation: (x - 1)(x - 2) = 0

8. Set each factor equal to zero and solve for x: x - 1 = 0 => x = 1 x - 2 = 0 => x = 2

So, the solutions to the equation are x = 1 and x = 2.