Question

11 (5(x+2y)-3=3x+5, (4(x-3y)-50=-22y;​

Answer 1

Ответ:

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Объяснение:

Answer 2

It appears that you have two linear equations:

1. $5(x+2y)-3=3x+5$
2. $4(x-3y)-50=-22y$

You can solve this system of equations using either the substitution method or the elimination method. Let's use the elimination method:

First, distribute the constants on the left side of the equations:

1. $5x + 10y - 3 = 3x + 5$
2. $4x - 12y - 50 = -22y$

Now, we can rearrange the equations to isolate the variable terms on one side and the constants on the other side:

1. $5x - 3x + 10y = 5 + 3$
2. $4x + 22y - 12y = 50$

Combine like terms:

1. $2x + 10y = 8$
2. $4x + 10y = 50$

Now, we have a system of two equations:

1. $2x + 10y = 8$
2. $4x + 10y = 50$

We can use the elimination method to eliminate the $10y$ term. Subtract equation (1) from equation (2) to eliminate $10y$:

$(4x + 10y) - (2x + 10y) = 50 - 8$

This simplifies to:

$2x = 42$

Now, divide both sides by 2 to solve for $x$:

$x = 21$

Now that we have found the value of $x$, we can substitute it back into either of the original equations to find $y$. Let's use equation (1):

$2x + 10y = 8$ $2(21) + 10y = 8$

Now, solve for $y$:

$42 + 10y = 8$

Subtract 42 from both sides:

$10y = 8 - 42$ $10y = -34$

Now, divide both sides by 10 to solve for $y$:

$y = -34 / 10$ $y = -3.4$

So, the solution to the system of equations is $x = 21$ and $y = -3.4$.