Question

1)13х(у+5х)-2х(у-6х)=? 2)5n²(3n+1)-2n(5n²-3)=? 3)х(х³+х²+х)-(х³+х²+х)=?

Answer 1

1)13х(у+5х)-2х(у-6х)=13xy+65x²- 2xy+12x²=11xy+77x²
2)5n²(3n+1)-2n(5n²-3)=15n³+5n²-10n³+6n= 5n³+ 5n²+6n
3)х(х³+х²+х)-(х³+х²+х)=x⁴+x³+x²-x³-x²-x= x⁴
извиняюсь если не правильно, но надеюсь , что правильно

Answer 2

Let's simplify the given expressions:

1. $13x(y+5x) - 2x(y-6x)$

First, distribute the terms inside the parentheses:

$13xy + 65x^2 - 2xy + 12x^2$

Combine the like terms:

$11xy + 77x^2$

So, $13x(y+5x) - 2x(y-6x) = 11xy + 77x^2$

2. $5n^2(3n+1) - 2n(5n^2-3)$

Distribute the terms:

$15n^3 + 5n^2 - 10n^3 + 6n$

Combine like terms:

$5n^3 + 5n^2 + 6n$

So, $5n^2(3n+1) - 2n(5n^2-3) = 5n^3 + 5n^2 + 6n$

3. $x(x^3+x^2+x) - (x^3+x^2+x)$

Distribute the terms:

$x^4 + x^3 + x^2 - x^3 - x^2 - x$

Combine like terms:

$x^4 - x$

So, $x(x^3+x^2+x) - (x^3+x^2+x) = x^4 - x$