Question

Log11 0.2+log 11 605

Answer 1

$log_{11}(0,2)+log_{11}(605)=log_{11}(0,2*605)=log_{11}(121)=log_{11}(11^2)=2$

Answer 2

To calculate the expression "log11(0.2) + log11(605)," we can use the logarithm property:

log_b(a) + log_b(c) = log_b(ac)

Applying this property, we get:

log11(0.2) + log11(605) = log11(0.2 * 605)

Now, we can calculate the product of 0.2 and 605:

0.2 * 605 = 121

Therefore, the expression simplifies to:

log11(0.2) + log11(605) = log11(121)

Now, we need to find the value of log11(121). In other words, we need to find the exponent to which we raise 11 to get 121:

11^x = 121

To solve for x, take the logarithm base 11 of both sides:

log11(11^x) = log11(121)

x = log11(121)

Since 11^2 = 121, the value of x is 2.

Therefore, the final result is:

log11(0.2) + log11(605) = log11(121) = 2