Question

(6c-5)(6c-5)-(6c-5)² при с=11 помогите плиз

Answer 1

(6c-5)(6c-5)-(6c-5)^2 =
(6c-5)(6c-5-6c+5) =
(6c-5)•0 = 0.

Answer 2

(6c-5)(6c-5)=(6c-5)² следовательно
(6c-5)(6c-5)-(6c-5)² =0 при любом c
Ответ: 0

Answer 3

Sure, I'd be happy to help you with that!

Let's substitute the value of "c" as 11 into the expression and simplify it step-by-step:

Given expression: (6c - 5)(6c - 5) - (6c - 5)²

Step 1: Substitute c = 11 into the expression: (6 * 11 - 5)(6 * 11 - 5) - (6 * 11 - 5)²

Step 2: Simplify the expressions inside the parentheses: (66 - 5)(66 - 5) - (66 - 5)²

Step 3: Perform the arithmetic inside the parentheses: (61)(61) - 61²

Step 4: Calculate the squares: 3721 - 61²

Step 5: Perform the final subtraction: 3721 - 3721

Step 6: The result is 0.

Therefore, when c = 11, the expression (6c - 5)(6c - 5) - (6c - 5)² equals 0.