Question

Y^2/ y+3 = y/ y+3 reshit

Answer 1

$\frac{y^2}{y + 3} = \frac{y}{y + 3}$
ОДЗ: y ≠ -3. 
Т.к. знаменатель не может быть нулем (ограничили в ОДЗ), домножим обе части уравнения на него. Получим 
y² = y
y² - y = 0
y(y - 1) = 0
y = 0 или y = 1. 

Ответ: -1; 0. 

Answer 2

Вот решение на рисунке дано

Answer 3

To solve the equation, we need to find the value of y that satisfies the equation:

$\frac{y^2}{y+3} = \frac{y}{y+3}$

First, let's get rid of the denominators by multiplying both sides of the equation by $(y+3)$:

$(y+3) \cdot \frac{y^2}{y+3} = (y+3) \cdot \frac{y}{y+3}$

The $(y+3)$ term in the denominators cancels out on both sides:

$y^2 = y$

Now, let's bring all the terms to one side of the equation to get it in standard quadratic form:

$y^2 - y = 0$

Now, we have a quadratic equation, and we can attempt to factor it:

$y(y - 1) = 0$

Now, using the zero-product property, we set each factor to zero and solve for y:

1. $y = 0$
2. $y - 1 = 0$ $y = 1$

So, the solutions to the equation are $y = 0$ and $y = 1$.