Question

0,2a*(5b^2c)+a^2b*(bc)^2+ab^2c

Answer 1

0,2a·(5b²c)+a²b·(bc)²+ab²c = ab²c + a²b·b²c² + ab²c = 2ab²c + a²b³c²

Answer 2

To simplify the expression, let's break it down and combine like terms:

Expression: 0.2a*(5b^2c) + a^2b*(bc)^2 + ab^2c

Step 1: Distribute the coefficients in the first and second terms: 0.2a * 5b^2c = 1a * 5b^2c = 5ab^2c a^2b * (bc)^2 = a^2b * b^2c^2 = a^2b^3c^2

Step 2: Combine like terms: 5ab^2c + a^2b^3c^2 + ab^2c

Step 3: Factor out the common term "ab^2c": ab^2c (5 + a^2bc + 1)

Final Simplified Expression: ab^2c(5 + a^2bc + 1)