Question

(x+2)(3x-1)=20срочно

Answer 1

(x+2)(3x-1)=20
3х²-х+6х-2=20
3х²+5х-22=0
D=25+4*3*22=289
x1=(-5+17)/2*3=12/6=2
x2=(-5-17)/2*3=-22/6=-11/3

Answer 2

To solve the equation (x+2)(3x-1) = 20, you need to find the value(s) of 'x' that make the equation true. Here's how you can do it:

Step 1: Expand the left-hand side of the equation: (x + 2)(3x - 1) = 20 3x^2 + 6x - x - 2 = 20 3x^2 + 5x - 2 = 20

Step 2: Move all the terms to one side of the equation to set it equal to zero: 3x^2 + 5x - 2 - 20 = 0 3x^2 + 5x - 22 = 0

Step 3: Now, you can either factor the quadratic equation or use the quadratic formula to find the values of 'x'. Let's use the quadratic formula: The quadratic formula states that for an equation of the form ax^2 + bx + c = 0, the solutions for 'x' are given by: x = (-b ± √(b^2 - 4ac)) / 2a

For our equation, a = 3, b = 5, and c = -22: x = (-(5) ± √(5^2 - 4 * 3 * -22)) / 2 * 3 x = (-5 ± √(25 + 264)) / 6 x = (-5 ± √289) / 6 x = (-5 ± 17) / 6

Now, we get two possible values for 'x':

1. x = (-5 + 17) / 6 x = 12 / 6 x = 2

2. x = (-5 - 17) / 6 x = -22 / 6 x = -11/3

So, the two solutions for the equation are x = 2 and x = -11/3.