Question

(4x-3)(6x-12)(4.8+0.6x)=0

Answer 1

(4х-3)(6х-12)(24/5+3/5х)=0
4х-3=0
6х-12=0
24/5+3/5х=0
х1=0,75
х2=2
х3=-8

Answer 2

To solve the equation $(4x-3)(6x-12)(4.8+0.6x) = 0$, we need to find the values of $x$ that make the equation true. To do this, we'll use the zero-product property, which states that if the product of two or more factors is equal to zero, then at least one of the factors must be equal to zero.

So, let's set each factor equal to zero and solve for $x$:

1. $4x-3 = 0$ Add 3 to both sides: $4x = 3$ Divide both sides by 4: $x = \frac{3}{4}$

2. $6x-12 = 0$ Add 12 to both sides: $6x = 12$ Divide both sides by 6: $x = 2$

3. $4.8+0.6x = 0$ Subtract 4.8 from both sides: $0.6x = -4.8$ Divide both sides by 0.6: $x = -8$

So, the solutions to the equation are $x = \frac{3}{4}$, $x = 2$, and $x = -8$. When $x$ takes on any of these values, the entire equation $(4x-3)(6x-12)(4.8+0.6x)$ will be equal to zero.