Question

Решите неравенство 8x+3(2x-1)⩽4 1)(-∞;0.5] 2)(-∞;-0.5] 3)(0.5;+∞] 4)[0.5;+∞)

Answer 1

$8x + 3(2x - 1) \leqslant 4 \\ 14x - 3 \leqslant 4 \\ 14x \leqslant 7 \\ x \leqslant 0.5$
х€(-бесконечность; 0,5]

Ответ: 1)

Answer 2

8x+6x-3-4⩽0
8x+6x-7⩽0
14x-7⩽0
14x⩽7
x⩽0.5
(-бесконечность;0.5]
1

Answer 3

To solve the inequality 8x + 3(2x - 1) ≤ 4, follow these steps:

1. Distribute the 3 on the left side: 8x + 6x - 3 ≤ 4

2. Combine the x terms: 14x - 3 ≤ 4

3. Add 3 to both sides of the inequality: 14x ≤ 7

4. Divide both sides by 14 to solve for x: x ≤ 7/14 x ≤ 0.5

So, the correct answer is option 1) (-∞; 0.5].