Question

Решите (2x-4) (3x+7) x-2

Answer 1

(2х-4)(3х+7) = 6х² + 14х - 12х -28 = 6х² +2х -28
при х = 2
6×2² +2×2 -28 = 6×4 +4 -28 = 24 +4 -28 = 28 -28 = 0
при х = -2
6×(-2)² +2(-2) -28 = 6×4 -4 -28 = 24 -4 -28 = 24 -32 = -8

Answer 2

To solve the expression, we need to perform the multiplication and then the subsequent subtraction. Let's proceed step-by-step:

Step 1: Perform the multiplication of the first two binomials (2x - 4) and (3x + 7) using the distributive property (FOIL method): (2x - 4) * (3x + 7) = 2x * 3x + 2x * 7 - 4 * 3x - 4 * 7 = 6x^2 + 14x - 12x - 28

Step 2: Simplify the expression obtained in Step 1: 6x^2 + (14x - 12x) - 28 = 6x^2 + 2x - 28

Step 3: Multiply the result from Step 2 by the variable x and then subtract 2: (6x^2 + 2x - 28) * x - 2 = 6x^3 + 2x^2 - 28x - 2

So, the simplified expression is 6x^3 + 2x^2 - 28x - 2.