Question

1) 3(х-8)-2=х+(4х-1) 2) х+25=4х-2(3х+3) 3) х=2(х-1)-4х

Answer 1

$3(x - 8) - 2 = \times + (4x - 1) \\ 3x - 24 - 2 = 5x - 1x \\ 3x + 1x - 5x = 24 + 2 \\ - x = 26 \\ x = - 26$

Answer 2

Let's solve each of these equations step by step:

1. 3(x - 8) - 2 = x + (4x - 1)

Expand the brackets:

3x - 24 - 2 = x + 4x - 1

Combine like terms:

3x - 26 = 5x - 1

Get all x terms on one side and constant terms on the other side:

3x - 5x = 26 - 1

-2x = 25

Now, isolate x by dividing by -2:

x = 25 / -2

x = -12.5

So the solution to the first equation is x = -12.5.

2. x + 25 = 4x - 2(3x + 3)

Distribute the -2 on the right side:

x + 25 = 4x - 6x - 6

Combine like terms:

x + 25 = -2x - 6

Get all x terms on one side and constant terms on the other side:

x + 2x = -6 - 25

3x = -31

Isolate x by dividing by 3:

x = -31 / 3

So the solution to the second equation is x = -31/3.

3. x = 2(x - 1) - 4x

Distribute the 2 on the right side:

x = 2x - 2 - 4x

Combine like terms:

x = -2x - 2

Get all x terms on one side and constant terms on the other side:

x + 2x = -2

3x = -2

Isolate x by dividing by 3:

x = -2 / 3

So the solution to the third equation is x = -2/3.

To summarize:

1. x = -12.5
2. x = -31/3
3. x = -2/3