Question

\frac{4с квадрат-9x квадрат}{2c-3x}

Answer 1

(2c-3x)*(2c+3x) /(2c-3x)=2c+3x.

Answer 2

To simplify the expression, we can factor the numerator and then cancel out any common factors with the denominator. The given expression is:

$\frac{4c^2 - 9x^2}{2c - 3x}$

First, we can factor the numerator using the difference of squares formula: $a^2 - b^2 = (a + b)(a - b)$

$4c^2 - 9x^2 = (2c)^2 - (3x)^2 = (2c + 3x)(2c - 3x)$

Now, our expression becomes:

$\frac{(2c + 3x)(2c - 3x)}{2c - 3x}$

We can see that there is a common factor of $2c - 3x$ in the numerator and denominator. Canceling it out, we get:

$2c + 3x$

So the simplified expression is $2c + 3x$.