Xy+x+y=9 x^2y+xy^2=20
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Решение///////////////////////////

To solve the system of equations:
- xy + x + y = 9 .......(Equation 1)
- x^2y + xy^2 = 20 .......(Equation 2)
We can use substitution or elimination. Let's use the substitution method:
Step 1: Solve Equation 1 for one variable in terms of the other. Let's solve for y:
xy + x + y = 9 y(x + 1) = 9 - x y = (9 - x) / (x + 1)
Step 2: Substitute the expression we found for y into Equation 2:
x^2y + xy^2 = 20 x^2[(9 - x) / (x + 1)] + x[(9 - x) / (x + 1)]^2 = 20
Step 3: Simplify the equation:
x^2(9 - x) + x(9 - x)^2 = 20(x + 1)
Step 4: Expand and rearrange the equation:
9x^2 - x^3 + x(81 - 18x + x^2) = 20x + 20 9x^2 - x^3 + 81x - 18x^2 + x^3 = 20x + 20
Step 5: Combine like terms:
9x^2 - 18x^2 + x^3 - x^3 - 20x = 20 - 81 -9x^2 - 20x + 61 = 0
Step 6: Now, we have a quadratic equation in terms of x. We can solve it using factoring, completing the square, or the quadratic formula. In this case, let's use the quadratic formula:
The quadratic formula states that for an equation in the form of ax^2 + bx + c = 0, the solutions for x are given by:
x = (-b ± √(b^2 - 4ac)) / 2a
In our equation, a = -9, b = -20, and c = 61. Substituting these values into the quadratic formula:
x = (20 ± √((-20)^2 - 4(-9)(61))) / 2(-9)
Step 7: Calculate the discriminant:
Discriminant = b^2 - 4ac Discriminant = (-20)^2 - 4(-9)(61) Discriminant = 400 + 2208 Discriminant = 2608
Step 8: Since the discriminant (2608) is positive, there are two real solutions for x:
x = (20 + √2608) / -18 or x = (20 - √2608) / -18
Step 9: Now, calculate the two values of x:
x = (20 + √2608) / -18 ≈ -2.6936 or x = (20 - √2608) / -18 ≈ 2.3599
Step 10: Finally, substitute the values of x back into the expression we found for y:
For x ≈ -2.6936: y = (9 - (-2.6936)) / (-2.6936 + 1) ≈ 4.5263
For x ≈ 2.3599: y = (9 - 2.3599) / (2.3599 + 1) ≈ 2.1869
So, the two sets of solutions to the system of equations are approximately:
- x ≈ -2.6936, y ≈ 4.5263
- x ≈ 2.3599, y ≈ 2.1869
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