Question

F(x)=7x^{2}-56x+8, x_{0}=4

Answer 1

Найти экстремум функции:

f(x)=7x^2-56x+8

через производную

(7x^2-56x+8 ) ' =0

14x -56 =0

14x =56

x =4

f(4) = 7*4^2-56*4+8= -104

ОТВЕТ (4; -104)

Answer 2

To find the value of the function F(x) at x = x₀ = 4, you simply need to substitute x = 4 into the function and perform the calculations.

Given the function F(x) = 7x^2 - 56x + 8, substitute x = 4:

F(4) = 7(4)^2 - 56(4) + 8

Now calculate:

F(4) = 7(16) - 224 + 8

F(4) = 112 - 224 + 8

F(4) = -104 + 8

F(4) = -96

Therefore, F(4) = -96.