Question

Y^2+8x=16 , y^2-24x=48

Answer 1

Решение в приложенном файле.

Ответ: (-1; 2√6)V(-1; -2√6)

Answer 2

To find the solution to the given system of equations:

1. y^2 + 8x = 16 ...........(Equation 1)
2. y^2 - 24x = 48 ...........(Equation 2)

Let's solve the system step by step:

Step 1: Subtract Equation 2 from Equation 1 to eliminate the y^2 term:

(y^2 + 8x) - (y^2 - 24x) = 16 - 48

Simplify the equation:

32x = -32

Step 2: Divide both sides by 32 to solve for x:

x = -32 / 32

x = -1

Step 3: Now that we have the value of x, we can substitute it back into either Equation 1 or Equation 2 to find the value of y. Let's use Equation 1:

y^2 + 8(-1) = 16

y^2 - 8 = 16

Step 4: Move the constant term to the other side:

y^2 = 16 + 8

y^2 = 24

Step 5: Take the square root of both sides to solve for y:

y = ±√24

y = ±2√6

So, the solutions to the system of equations are:

1. x = -1, y = 2√6
2. x = -1, y = -2√6