Question

(а-2)в квадрате (x-5) (x+5)(2a+3b) два в квадрате (4х-х) (х+4х)

Answer 1

А^2 - 4а + 4
х^2 - 25
-
х^2 - 16x^2

Answer 2

Let's simplify the given expressions step by step:

1. (а-2)²: To square the binomial (а-2), we can use the formula for squaring a binomial: (a - b)² = a² - 2ab + b².

So, for (а-2)², we have: (а-2)² = а² - 2 * а * 2 + 2² = а² - 4а + 4

2. (x-5) (x+5) (2a+3b): To multiply these three binomials, we can use the distributive property to expand the expression.

(x-5) (x+5) (2a+3b) = (x² - 5x + 5x - 25) (2a + 3b) = (x² - 25) (2a + 3b) = 2a(x²) + 2a(-25) + 3b(x²) + 3b(-25) = 2ax² - 50a + 3bx² - 75b = (2a + 3b) * x² - 50a - 75b

3. два в квадрате (4х-х) (х+4х): First, let's simplify the expressions inside the brackets: (4х-х) = 3х (х+4х) = 5х

Now, we have: два в квадрате (3х) (5х) = 2² * 3х * 5х = 4 * 3х * 5х = 60х²

Therefore, the final simplified expressions are:

1. (а-2)² = а² - 4а + 4
2. (x-5) (x+5) (2a+3b) = (2a + 3b) * x² - 50a - 75b
3. два в квадрате (4х-х) (х+4х) = 60х²