Question

Lg(4+3x) lg(5x+4)=0 решите пж

Answer 1

Решение на фото

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Answer 2

To solve the equation lg(4+3x) * lg(5x+4) = 0, we need to find the values of x that satisfy the equation. To do this, we can use the property of logarithms that states:

If lg(a) * lg(b) = 0, then either lg(a) = 0 or lg(b) = 0.

So, we can set each factor inside the logarithms equal to 0 and solve for x:

1. lg(4 + 3x) = 0: lg(4 + 3x) = 0 Now, we can convert the equation to its exponential form: 10^0 = 4 + 3x 1 = 4 + 3x 3x = 1 - 4 3x = -3 x = -3/3 x = -1

2. lg(5x + 4) = 0: lg(5x + 4) = 0 Now, we can convert the equation to its exponential form: 10^0 = 5x + 4 1 = 5x + 4 5x = 1 - 4 5x = -3 x = -3/5

So, the solutions to the equation are x = -1 and x = -3/5.