Question

Найдите значение функции 16х^2+10х-21 при х = 2.

Answer 1

16х^2+10х-21=(2х+3)(8х-7)
Если х=2, то:
(2*2+3)(8*2-7)=(4+3)(16-7)=7*9=63
Ответ: 63

Answer 2

To find the value of the function 16x^2 + 10x - 21 when x = 2, you simply need to substitute x with 2 in the expression and perform the calculation:

f(x) = 16x^2 + 10x - 21

f(2) = 16(2)^2 + 10(2) - 21 = 16(4) + 20 - 21 = 64 + 20 - 21 = 84 - 21 = 63

So, when x = 2, the value of the function 16x^2 + 10x - 21 is 63.