Question

(3+7х)^2-х《-26+х (49х-8) решите неравенства 4+(6-11х)^2>25х+х (121х+3)

Answer 1

если это система то напиши в комментариях я исправлю

Answer 2

To solve the inequalities, let's start with the first one:

(3 + 7x)^2 - x ≤ -26 + x(49x - 8)

Step 1: Expand the squared term on the left side.

(9 + 42x + 49x^2) - x ≤ -26 + 49x^2 - 8x

Step 2: Combine like terms on both sides.

49x^2 + 41x + 9 ≤ 49x^2 - 8x - 26

Step 3: Move all terms to one side of the inequality.

0 ≤ -8x - 8x - 26 - 9

0 ≤ -16x - 35

Step 4: Move the constant term to the other side by changing the sign.

16x + 35 ≥ 0

Step 5: Solve for x.

16x ≥ -35

x ≥ -35/16

So the solution for the first inequality is x ≥ -35/16.

Now, let's solve the second inequality:

4 + (6 - 11x)^2 > 25x + x(121x + 3)

Step 1: Expand the squared term on the left side.

4 + (36 - 132x + 121x^2) > 25x + 121x^2 + 3x

Step 2: Combine like terms on both sides.

4 + 121x^2 - 132x + 36 > 124x + 121x^2

Step 3: Simplify the equation.

4 - 132x + 36 > 124x

Step 4: Move all terms to one side of the inequality.

40 > 124x + 132x

40 > 256x

Step 5: Divide by the coefficient of x (256) to solve for x.

x < 40/256

x < 5/32

So the solution for the second inequality is x < 5/32.

To summarize:

1. The solution for the first inequality is x ≥ -35/16.
2. The solution for the second inequality is x < 5/32.