Question

-3 1/5a^8b*(1/2a^3b^8)^4

Answer 1

$-3\frac{1}{5} a^{8}b*(\frac{1}{2}a^{3}b^{8})^{4}=-\frac{16}{5}a^{8}b*\frac{1}{16}a^{12}b^{32}=-\frac{16}{5}*\frac{1}{16}a^{8+12}b^{1+32}=-0,2a^{20} b^{33}$

Answer 2

To simplify the expression, let's start by performing the operations step by step:

1. Multiply the coefficients: -3 * (1/2)^4 = -3 * 1/16 = -3/16

2. Simplify the bases with exponents: a^8 * a^(3*4) = a^8 * a^12 = a^(8+12) = a^20

b^1 * b^(8*4) = b * b^32 = b^(1+32) = b^33

Now, put it all together:

-3 1/5a^8b*(1/2a^3b^8)^4 = -3/16 * a^20 * b^33