Question

(y-1)(y+1) (5a²-3c³)²

Answer 1

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Готово!!Удачи)))

Answer 2

(y-1)(y+1)=y²-1

(5a²-3c³)²=25a^4+30a²c³+9c^6

Answer 3

To simplify the expression, let's start by expanding each set of parentheses and then combining like terms, if any.

1. (y - 1)(y + 1): Using the difference of squares formula (a^2 - b^2 = (a + b)(a - b)), we can simplify this as follows: (y - 1)(y + 1) = y^2 - 1^2 = y^2 - 1

2. (5a^2 - 3c^3)^2: To square this binomial, we'll multiply it by itself: (5a^2 - 3c^3)^2 = (5a^2 - 3c^3)(5a^2 - 3c^3)

Now, let's expand the squared expression using the distributive property:

(5a^2 - 3c^3)(5a^2 - 3c^3) = 5a^2 * 5a^2 + 5a^2 * (-3c^3) - 3c^3 * 5a^2 - 3c^3 * (-3c^3)

Simplifying further:

= 25a^4 - 15a^2c^3 - 15a^2c^3 + 9c^6 = 25a^4 - 30a^2c^3 + 9c^6

Now, let's put the simplified expressions together:

(y - 1)(y + 1)(5a^2 - 3c^3)^2 = (y^2 - 1)(25a^4 - 30a^2c^3 + 9c^6)

At this point, we have the expression in its fully expanded form. Depending on the context or specific problem, you may need to further simplify or factorize the expression.