Question

(-x-5)(2x+4)=0 (-x-4)(3x+3)=0

Answer 1

(-х-5)(2х+4)=0

-2х^2-4х-20-10х=0

-2х^2-14х-20=0 |:(-2)

х^2+7х+20=0

д=49-80=-31 т.к д<0 то в ур-ие нет корней

(-х-4)(3х+3)=0

-3х^2-3х-12х-12=0

-3х^2-15х-12=0 |:(-3)

х^2+5х+4=0

д=25-16=9

х1=(-5-3):2=-4 х2=(-5+3):2=-1

Answer 2

(-х-5)(2х+4)=0

-2х^2-4х-10х-20=0

-2х^2-14х-20=0

a=-2, b=-14, c=-20

D=196-160=36

D>0, 2 корня.

x(1)=(14-6):(-4)= -2

x(2)=(14+6):(-4)= -5

(-x-4)(3x+3)=0

-3x^2-3x-12x-12=0

-3х^2-15х-12=0

a=-3, b=-15, c=-12

D=225-144=81

D>0, 2 корня.

х(1)=(15-9):(-6)= -1

х(2)=(15+9):(-6)= -4

Answer 3

To find the solutions for the given equations, set each expression equal to zero and solve for the variable "x."

1. (-x - 5)(2x + 4) = 0

To find the solutions for this equation, set each factor equal to zero and solve for "x":

Set -x - 5 = 0: -x = 5 x = -5

Set 2x + 4 = 0: 2x = -4 x = -4 / 2 x = -2

So, the solutions for the first equation are x = -5 and x = -2.

2. (-x - 4)(3x + 3) = 0

Similarly, set each factor equal to zero and solve for "x":

Set -x - 4 = 0: -x = 4 x = -4

Set 3x + 3 = 0: 3x = -3 x = -3 / 3 x = -1

The solutions for the second equation are x = -4 and x = -1.

To summarize:

1. For the equation (-x - 5)(2x + 4) = 0, the solutions are x = -5 and x = -2.
2. For the equation (-x - 4)(3x + 3) = 0, the solutions are x = -4 and x = -1.