Question

1. 5*(2x-6)+3(x-1) = 2. (-3x2y)2*(1/3xy)3 =

Answer 1

Первое получается 10х-30+3х-3= 13х-30-3 = 13х-33
второе получается -6ху*2*1/3ху*3=-6ху*2ху=-12х(в квадрате)у(в квадрате)

Answer 2

Let's solve each equation step by step:

1. 5*(2x-6) + 3*(x-1) = 2

Step 1: Distribute the numbers outside the parentheses. 10x - 30 + 3x - 3 = 2

Step 2: Combine like terms on the left side. (10x + 3x) + (-30 - 3) = 2 13x - 33 = 2

Step 3: Move the constant term to the right side by adding 33 to both sides. 13x = 2 + 33 13x = 35

Step 4: Solve for x by dividing both sides by 13. x = 35 / 13

So, the solution for the equation is: x = 35 / 13 ≈ 2.6923

2. (-3x^2y)^2 * (1/3xy)^3

Step 1: Simplify the exponents within the parentheses. (-3)^2 * (x^2)^2 * y^2 * (1/3)^3 * x^3 * y^3

Step 2: Evaluate the exponents. 9 * x^(2*2) * y^2 * (1/27) * x^3 * y^3

Step 3: Simplify further. 9 * x^4 * y^2 * (1/27) * x^3 * y^3

Step 4: Combine the constants. (9 * 1/27) * x^(4+3) * y^(2+3)

Step 5: Simplify the constants. (1/3) * x^7 * y^5

So, the final result is: (1/3) * x^7 * y^5