Question

[x - y = 6,x + xy = -4; способом подстановки решите систему уравнений​

Answer 1

Ответ:

вот ответ))))))))

*не забудь, пожалуйста, отметить мой ответ как лучший)

Answer 2

To solve the system of equations by substitution, we will solve one equation for one variable and substitute it into the other equation. Let's solve the first equation for x:

x - y = 6

Rearrange the equation to solve for x:

x = 6 + y

Now substitute this expression for x into the second equation:

(6 + y) + y(6 + y) = -4

Simplify the equation:

6 + y + 6y + y^2 = -4

Rearrange the equation to a quadratic form:

y^2 + 7y + 10 = 0

Factor the quadratic equation:

(y + 5)(y + 2) = 0

This gives us two possible values for y:

y + 5 = 0 => y = -5 or y + 2 = 0 => y = -2

Now substitute these values of y back into the equation x = 6 + y to find the corresponding values of x:

For y = -5: x = 6 + (-5) = 1

For y = -2: x = 6 + (-2) = 4

Therefore, the solution to the system of equations is x = 1, y = -5 and x = 4, y = -2.