Question

(a-c)2-(a2-c2)+2ac-2=2(c2-1)

Answer 1

Ответ:

a=2, c=0

Объяснение:

Раскрываем скобки

2a-2c -2a+2c +2ac-2 = 4c-2

2ac-4c=0

2c(a-2)=0

a-2=0 или 2c=0

a=2, c=0

Answer 2

Let's simplify the equation step by step:

Starting with the left side of the equation: (a - c)^2 - (a^2 - c^2) + 2ac - 2

Expanding the square: (a^2 - 2ac + c^2) - (a^2 - c^2) + 2ac - 2

Simplifying the expression inside the parentheses: a^2 - 2ac + c^2 - a^2 + c^2 + 2ac - 2

Combining like terms: -2ac + 2c^2 + 2ac - 2

The -2ac and 2ac terms cancel each other out: 2c^2 - 2

Now, let's simplify the right side of the equation: 2(c^2 - 1)

Expanding the parentheses: 2c^2 - 2

Comparing the left and right sides of the equation: 2c^2 - 2 = 2c^2 - 2

We can see that both sides of the equation are equal. Therefore, the given equation is true for any value of c.