Question

[18÷(-3)³–7-²×5,(4)]×(х-1)=√4+2х

Answer 1

это если не надо расписывать это сам ответ

Answer 2

Let's simplify the given expression step by step:

1. Evaluate the terms inside the parentheses first: 18 ÷ (-3)³ = 18 ÷ (-27) = -2/3 7^(-2) = 1/7² = 1/49

2. Now, simplify the expression inside the square root: √4 + 2x = √(4 + 2x) (Note: I assume you meant √(4 + 2x) and not √4 + 2x)

3. Combine the terms inside the parentheses: [-2/3 - 1/49 × 5, (4)] × (x - 1) = [-2/3 - 5/49] × (x - 1)

4. Find a common denominator for the terms inside the bracket: [-2/3 - 5/49] = [(-2 × 49)/(3 × 49) - 5/49] = [(-98 - 5)/49] = [-103/49]

5. Substitute the value inside the bracket back into the expression: [-103/49] × (x - 1)

6. Now, set the expression equal to √(4 + 2x): [-103/49] × (x - 1) = √(4 + 2x)

To solve for x, we need to isolate x on one side of the equation. Let's proceed with the steps:

7. Divide both sides of the equation by [-103/49]: x - 1 = √(4 + 2x) / (-103/49)

8. To get rid of the square root, square both sides: (x - 1)² = [√(4 + 2x) / (-103/49)]²

9. Simplify the right side: (x - 1)² = (4 + 2x) / [(103/49)²]

10. Expand the left side: (x² - 2x + 1) = (4 + 2x) / [(103/49)²]

11. Multiply both sides by [(103/49)²] to eliminate the fraction: (103/49)² × (x² - 2x + 1) = 4 + 2x

12. Expand the left side: (103/49)² × x² - (103/49)² × 2x + (103/49)² × 1 = 4 + 2x

13. Rearrange the equation to set it equal to zero: (103/49)² × x² - (103/49)² × 2x + (103/49)² × 1 - 4 - 2x = 0

14. Combine like terms: (103/49)² × x² - (103/49)² × 2x + (103/49)² - 4 - 2x = 0

15. Simplify further if needed.

Now, the above equation is a quadratic equation in terms of x. To find the values of x, you can use the quadratic formula or other appropriate methods for solving quadratic equations. Once you have the solutions for x, remember to check them in the original equation to ensure they are valid solutions.