Question

(2√5 - 3√5)*(2√5 + 3√5)

Answer 1

Ответ:

на листике................

Answer 2

Решаем через формулу разности квадратов:

$x^{2}-y^{2} =(x-y)*(x+y)$

$(2\sqrt{5}-3\sqrt{5})*(2\sqrt{5} + 3\sqrt{5})=4*5-9*5=20-45=-25$

Ответ: -25

Answer 3

To simplify the expression (2√5 - 3√5)(2√5 + 3√5), you can use the difference of squares formula: (a - b)(a + b) = a^2 - b^2.

In this case, let's consider 2√5 as "a" and 3√5 as "b". Applying the formula, we have:

(2√5 - 3√5)(2√5 + 3√5) = (2√5)^2 - (3√5)^2

Simplifying the terms within the formula, we get:

= (4 * 5) - (9 * 5)

= 20 - 45

= -25

Therefore, (2√5 - 3√5)(2√5 + 3√5) simplifies to -25.