Question

(х -7)(x+3) + (х-1)(x+5) + 26-0​

Answer 1

(x-7)(x+3) +(x-1)(x+5) + 26 = 0

x2 + 3x - 7x - 21 + x2 + 5x - x - 5 +26 = 0

2x2 = 0

x = 0

(x2 это х в квадрате)

Answer 2

To simplify the expression, let's expand and combine like terms:

(x - 7)(x + 3) + (x - 1)(x + 5) + 26 - 0

Expanding the first two terms:

(x^2 + 3x - 7x - 21) + (x^2 + 5x - x - 5) + 26 - 0

Combining like terms:

(x^2 - 4x - 21) + (x^2 + 4x - 5) + 26 - 0

Combining like terms again:

2x^2 - 26 + 26

The -4x and 4x terms cancel each other out, and 26 - 26 results in 0, leaving us with:

2x^2

So the simplified expression is 2x^2.