Question

A: 2x²+6x+b=0 b: 5x²-4x+3b=0 c:3x²+bx+3=0 d: x²+bx+5=0

Answer 1

Ответ:

a: 8x(3 степень)+b=0

b: x+3b=0

c: 3x(3 cтепень)b+3=0

d: x(3 степень)b+5=0

Answer 2

To find the value of "b" in each of the given quadratic equations, we can use the quadratic formula. The quadratic formula states that for a quadratic equation of the form ax² + bx + c = 0, the solutions for x can be calculated using:

x = (-b ± √(b² - 4ac)) / 2a

Let's apply this formula to each equation to find the value of "b."

a) 2x² + 6x + b = 0 In this equation, a = 2, b = 6, and c = b. Substituting the values into the quadratic formula:

x = (-(6) ± √(6² - 4 * 2 * b)) / (2 * 2)

x = (-6 ± √(36 - 8b)) / 4

b) 5x² - 4x + 3b = 0 In this equation, a = 5, b = -4, and c = 3b. Substituting the values into the quadratic formula:

x = (-(4) ± √((-4)² - 4 * 5 * 3b)) / (2 * 5)

x = (-4 ± √(16 - 60b)) / 10

c) 3x² + bx + 3 = 0 In this equation, a = 3, b = b, and c = 3. Substituting the values into the quadratic formula:

x = (-(b) ± √(b² - 4 * 3 * 3)) / (2 * 3)

x = (-b ± √(b² - 36)) / 6

d) x² + bx + 5 = 0 In this equation, a = 1, b = b, and c = 5. Substituting the values into the quadratic formula:

x = (-(b) ± √(b² - 4 * 1 * 5)) / (2 * 1)

x = (-b ± √(b² - 20)) / 2

At this point, we have the expressions for the solutions of x in terms of "b" for each of the equations. However, to find the value of "b" in each equation, we would need more information or context. As it stands, we have a relationship between "x" and "b" but not a specific value for "b" in any of the equations.