Question

1) (3a+4)(7a+2) 2) (2x+3)(4x²-3x+2) 3) (3x-5)(4x+1)-(2x+3)(6x+4)​

Answer 1

Ответ:

1) 21а²+6а+28а+8=21а²+34+8.

2) 8х³-6х²+4х+12х²-9х+6=9х³+6х²-5х+6.

3) 13х²+3х-20х-5-(12х²+8х+18х+12)=12х²+3х-20х-5-12х²-8х-18х-12=-43х-17.

Объяснение:

мы умножаем дугой. Объясню на 1 примере: 3а×7а+3а×2+4×7а+4×2, затем ищем подобные и выполняем действия.

Answer 2

Let's simplify the given expressions:

1. (3a + 4)(7a + 2):

To expand this expression, we can use the distributive property. We multiply each term in the first expression (3a + 4) by each term in the second expression (7a + 2), and then combine like terms:

(3a + 4)(7a + 2) = 3a * 7a + 3a * 2 + 4 * 7a + 4 * 2 = 21a² + 6a + 28a + 8 = 21a² + 34a + 8

Therefore, the expanded form of (3a + 4)(7a + 2) is 21a² + 34a + 8.

2. (2x + 3)(4x² - 3x + 2):

Following the same procedure as above, we multiply each term in the first expression (2x + 3) by each term in the second expression (4x² - 3x + 2):

(2x + 3)(4x² - 3x + 2) = 2x * 4x² + 2x * (-3x) + 2x * 2 + 3 * 4x² + 3 * (-3x) + 3 * 2 = 8x³ - 6x² + 4x + 12x² - 9x + 6 = 8x³ + 6x² - 5x + 6

Therefore, the expanded form of (2x + 3)(4x² - 3x + 2) is 8x³ + 6x² - 5x + 6.

3. (3x - 5)(4x + 1) - (2x + 3)(6x + 4):

Using the distributive property, we can expand this expression:

(3x - 5)(4x + 1) - (2x + 3)(6x + 4) = (3x * 4x + 3x * 1 - 5 * 4x - 5 * 1) - (2x * 6x + 2x * 4 + 3 * 6x + 3 * 4) = (12x² + 3x - 20x - 5) - (12x² + 8x + 18x + 12) = 12x² + 3x - 20x - 5 - 12x² - 8x - 18x - 12 = 12x² - 20x - 12x² + 3x - 8x - 18x - 5 - 12 = -8x - 23

Therefore, the simplified form of (3x - 5)(4x + 1) - (2x + 3)(6x + 4) is -8x - 23.