Question

(1+x) (x+2) (3+x) (x+4) при x= - 1/3(дробь)​

Answer 1

Ответ:

Если не ошибаюсь, то вот решение.

Answer 2

To evaluate the expression (1+x)(x+2)(3+x)(x+4) at x = -1/3, we substitute the given value into the expression and calculate the result.

Let's substitute x = -1/3 into the expression:

(1 + (-1/3))((-1/3) + 2)(3 + (-1/3))((-1/3) + 4)

Now simplify the expression:

(2/3)(5/3)(8/3)(11/3)

Multiplying the fractions together:

2 * 5 * 8 * 11

3 * 3 * 3 * 3

= 880/81

Therefore, when x = -1/3, the expression (1+x)(x+2)(3+x)(x+4) evaluates to 880/81.