Question

∆=|5 а| |3 12|Найдите значение параметра а, при котором определитель ∆ равен 0.​

Answer 1

Ответ:

∆=5*12-3*а=0, 60=3а, а=20 -ответ

Answer 2

To find the value of the parameter "a" for which the determinant ∆ is equal to 0, we need to set up and solve the equation:

∆ = |5a 3| | 3 12|

The determinant of a 2x2 matrix can be calculated as:

∆ = (5a * 12) - (3 * 3)

Simplifying further:

∆ = 60a - 9

Now, we can set ∆ equal to 0 and solve for "a":

0 = 60a - 9

Adding 9 to both sides of the equation:

60a = 9

Dividing both sides by 60:

a = 9/60

Simplifying the fraction:

a = 3/20

Therefore, the value of the parameter "a" for which the determinant ∆ is equal to 0 is a = 3/20.