Question

2arcsin(√2/2)+3arcctg0​

Answer 1

Ответ:

$2\pi$

Объяснение:

$2arcsin(\frac{\sqrt{2} }{2} )+3arcctg0=2*\frac{\pi }{4}+3*\frac{\pi }{2}=\frac{\pi }{2} +\frac{3\pi }{2}=\frac{4\pi }{2} =2\pi$

Answer 2

Ответ: по свойствам функций 2*0,25*pi+3*pi/2=0,5*pi+1,5*pi=2*pi. Всё просто.

Объяснение:

Answer 3

To simplify the given expression, let's evaluate each trigonometric function:

1. arcsin(√2/2): The value of arcsin(√2/2) is π/4 radians or 45 degrees. This is because sin(π/4) = √2/2.

2. arcctg(0): The value of arcctg(0) is π/2 radians or 90 degrees. This is because ctg(π/2) = 0.

Now, let's substitute the values into the expression:

2arcsin(√2/2) + 3arcctg(0) = 2(π/4) + 3(π/2) = π/2 + 3π/2 = 2π

Therefore, 2arcsin(√2/2) + 3arcctg(0) simplifies to 2π.