Question

2x² + x -1 = 3x + 1;x + 1​

Answer 1

Ответ:

2x^2 + 2x-1=0

D=4-4×2×(-1)=-4

Объяснение:

меніңше осылай

Answer 2

To solve the equation 2x² + x - 1 = 3x + 1; x + 1, we need to find the value of x that satisfies this equation.

Let's simplify the equation and solve for x step by step:

1. Start by expanding the expression x + 1 to get rid of the parentheses: 2x² + x - 1 = 3x + 1; x + 1 2x² + x - 1 = 3x + 1; x + 1x + 1

2. Combine like terms on each side of the equation: 2x² + x - 1 = 3x + 1; x² + 2x + 1

3. Move all terms to one side of the equation to set it equal to zero: 2x² + x - 3x - 1 = 1; x² + x - 2 = 0

4. Rearrange the equation in descending order: 2x² - 2 + x = 0; x² + x - 2 = 0

5. Now we can solve the quadratic equation x² + x - 2 = 0. We can factor it: (x + 2)(x - 1) = 0

6. Set each factor equal to zero and solve for x: x + 2 = 0 or x - 1 = 0

   For x + 2 = 0, we subtract 2 from both sides: x = -2

   For x - 1 = 0, we add 1 to both sides: x = 1

So the solutions to the equation 2x² + x - 1 = 3x + 1; x + 1 are x = -2 and x = 1.