Question

-2x(x²-x+3)+x(2x²+x-5)при x = 3​

Answer 1

-2x³+2x²-6x+2x³+x²-5x= 3x²-11x= 3*9-11*3= 27-33= -6

Answer 2

To evaluate the expression -2x(x²-x+3) + x(2x²+x-5) when x = 3, follow these steps:

Step 1: Replace each instance of "x" in the expression with the value 3. Step 2: Perform the operations according to the order of operations (PEMDAS/BODMAS).

Let's calculate it step by step:

Step 1: -2 * 3(3² - 3 + 3) + 3(2 * 3² + 3 - 5)

Step 2: -2 * 3(9 - 3 + 3) + 3(2 * 9 + 3 - 5)

Step 3: -2 * 3(9) + 3(2 * 9 + 3 - 5)

Step 4: -2 * 27 + 3(18 + 3 - 5)

Step 5: -54 + 3(16)

Step 6: -54 + 48

Step 7: -6

Therefore, when x = 3, the expression -2x(x²-x+3) + x(2x²+x-5) evaluates to -6.