Question

1) 2•(3-5)= 2) (2a-3c) (a+2c)=3) (y-1)•(+2y-4)=1) 2в•в=2) 3b•=

Answer 1

Ответ:

1)6х`2-10х`5

2)2а`2+ас-6с`2

3)у`3+у`2-6у+4

1)2а`8в`2

2)3а`6в`з

Объяснение:

Все так просто

Answer 2

Let's solve the expressions step by step:

1. 2 • (3 - 5) = 2 • (-2) = -4

2. (2a - 3c) • (a + 2c) = 2a^2 + 4ac - 3ac - 6c^2 = 2a^2 + ac - 6c^2

3. (y - 1) • (2y - 4) = 2y^2 - 4y - 2y + 4 = 2y^2 - 6y + 4

4. 2в • в = (2b) • (в) = 2bв (This expression cannot be simplified further without more information about the variables).

5. 3b • (empty space) = It seems there is an error in the expression. It is missing the second part of the multiplication (empty space). Please provide the complete expression to proceed with the calculation.

If you have any other expressions or need further clarification, feel free to ask!