Question

-15=2х-х^2Квадратное уровнение ​

Answer 1

Ответ:

Объяснение:

x²-2x-15=0

D= 4+60= 64

x1= (2+8)/2= 5

x2= (2-8)/2= -3

Answer 2

To solve the quadratic equation -15 = 2x - x^2, we first need to rewrite it in standard form, which is ax^2 + bx + c = 0.

The given equation is already in the correct form: -x^2 + 2x - 15 = 0

Now, we can solve the equation using the quadratic formula: x = (-b ± √(b^2 - 4ac)) / 2a

In this case, a = -1, b = 2, and c = -15. Plugging these values into the formula, we get:

x = (-(2) ± √(2^2 - 4(-1)(-15))) / 2(-1) x = (-2 ± √(4 - 60)) / -2 x = (-2 ± √(-56)) / -2

The expression under the square root (√) is negative, which means the equation has complex roots. To simplify the calculation, we can write √(-56) as √(56) * √(-1). The square root of -1 is represented as "i" in complex numbers.

x = (-2 ± √(56)i) / -2

Now, we can factor out -1 from the numerator:

x = -(-2 ± √(56)i) / 2 x = (2 ± √(56)i) / 2

Finally, we can simplify further by dividing both the numerator and denominator by 2:

x = 1 ± (√(56)i)

So, the solutions to the quadratic equation -15 = 2x - x^2 are:

x = 1 + √(56)i x = 1 - √(56)i