Question

0,5<a<0,8. 1) a-b, 2) a/b, 3)3b/2a​

Answer 1

Ответ:

1)-0,3<a

2) извини, незнаю

3)24>a

Answer 2

To find the values of the expressions (a-b), (a/b), and (3b/2a) using the given inequality 0.5 < a < 0.8, we need to determine the range of 'a' and then compute the values accordingly.

Given: 0.5 < a < 0.8

1. a - b: Since we don't have any specific value for 'b,' we can't determine the exact value of (a - b). All we know is that 'a' lies between 0.5 and 0.8, but without knowing the value of 'b,' we can't find the value of (a - b).

2. a/b: To find the range of (a/b), we need to consider the extreme values of 'a' and 'b' that satisfy the given inequality.

For the minimum value of 'a' (0.5) and the maximum value of 'b' (0.8), we get: (a/b) = 0.5 / 0.8 = 0.625

For the maximum value of 'a' (0.8) and the minimum value of 'b' (0.5), we get: (a/b) = 0.8 / 0.5 = 1.6

So, the range of (a/b) is 0.625 < (a/b) < 1.6.

3. 3b/2a: To find the range of (3b/2a), we again consider the extreme values of 'a' and 'b' that satisfy the given inequality.

For the minimum value of 'a' (0.5) and the maximum value of 'b' (0.8), we get: (3b/2a) = (3 * 0.8) / (2 * 0.5) = 1.2

For the maximum value of 'a' (0.8) and the minimum value of 'b' (0.5), we get: (3b/2a) = (3 * 0.5) / (2 * 0.8) = 0.9375

So, the range of (3b/2a) is 0.9375 < (3b/2a) < 1.2.

To summarize:

1. a - b: The value of (a - b) cannot be determined without knowing the value of 'b.'
2. a/b: The range of (a/b) is 0.625 < (a/b) < 1.6.
3. 3b/2a: The range of (3b/2a) is 0.9375 < (3b/2a) < 1.2.