Question

(c-1/6)(1/36+c^2)(1/6+c) при c=1/6

Answer 1

(1/6-1/6)(1/36+(1/6)^2)(1/6+1/6)=0(1/36+1/36)(1/6+1/6)=

=2/6

Answer 2

To evaluate the expression (c-1/6)(1/36+c^2)(1/6+c) at c = 1/6, we simply need to substitute c with the given value and perform the calculations. Here's the step-by-step process:

Step 1: Substitute c with 1/6 in the expression. (c - 1/6)(1/36 + c^2)(1/6 + c) = (1/6 - 1/6)(1/36 + (1/6)^2)(1/6 + 1/6)

Step 2: Simplify the expression within the parentheses. (0)(1/36 + 1/36^2)(1/6 + 1/6) (0)(1/36 + 1/36^2)(1/3)

Step 3: Continue simplification. (0)(1/36 + 1/1296) 0(0.027777... + 0.000771604...) 0(0.028548604...)

Step 4: The final result is 0.

Therefore, when c = 1/6, the expression evaluates to 0.