Question

(b+2)(b2-2b+4)-b(b2-1)

Answer 1

Ответ:

8-b.

Объяснение:

(b+2)(b²-2b+4)-b(b²-1) = (b³+8)-(b³+b) = 8-b

Answer 2

Let's simplify the given expression step by step:

First, let's expand the expression: (b+2)(b^2-2b+4)-b(b^2-1)

Expanding the first part: (b^2-2b+4)(b^2-1)

Now, let's distribute the terms: b^2(b^2-1) - 2b(b^2-1) + 4(b^2-1)

Expanding each term: b^4 - b^2 - 2b^3 + 2b - 4b^2 + 4 + 4b^2 - 4

Combining like terms: b^4 - 2b^3 - b^2 + 2b + 4

So, the simplified expression is b^4 - 2b^3 - b^2 + 2b + 4.